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GraphQLError is just an interface and anybody is free to create a custom exception which also implements the GraphQLError interface. So think that's the main reason this condition exists.
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oliemansm commentedon Jan 22, 2022
GraphQLErroris just an interface and anybody is free to create a custom exception which also implements theGraphQLErrorinterface. So think that's the main reason this condition exists.I'll convert this issue to a Discussion btw.