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CPU-Code
java
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java
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nowCoder
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src
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com
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cpucode
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hash
/
two
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sum
/
TwoSumTest.java
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package com.cpucode.hash.two.sum;
import java.util.HashMap;
import java.util.Map;
/**
* 两数之和
*
* 描述
* 给出一个整数数组,请在数组中找出两个加起来等于目标值的数,
* 你给出的函数twoSum 需要返回这两个数字的下标(index1,index2),
* 需要满足 index1 小于index2.。注意:下标是从1开始的 , 假设给出的数组中只存在唯一解
* 例如:
* 给出的数组为 {20, 70, 110, 150},目标值为90
* 输出 index1=1, index2=2
*
* 示例1
* 输入:
* [3,2,4],6
*
* 返回值:
* [2,3]
* 说明:
* 因为 2+4=6 ,而 2的下标为2 , 4的下标为3 ,又因为 下标2 < 下标3 ,所以输出[2,3]
*
* @author : cpucode
* @date : 2021/6/5
* @time : 22:35
* @github : https://github.com/CPU-Code
* @csdn : https://blog.csdn.net/qq_44226094
*/
public class TwoSumTest {
public static void main(String[] args) {
int[] numbers = {3, 2, 4};
TwoSumTest twoSumTest = new TwoSumTest();
int[] ints = twoSumTest.twoSum(numbers, 6);
for (int anInt : ints) {
System.out.print(anInt + " ");
}
}
/**
* @param numbers int整型一维数组
* @param target int整型
* @return int整型一维数组
*/
public int[] twoSum (int[] numbers, int target) {
Map<Integer, Integer> map = new HashMap<>();
int[] res = new int[2];
for (int i = 0; i < numbers.length; i++) {
if (map.containsKey(target - numbers[i])){
res[0] = map.get(target - numbers[i]);
res[1] = i + 1;
return res;
}else{
map.put(numbers[i], i + 1);
}
}
return res;
}
}
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